3a+5a(2a+4ab-1a)=
asked by guest on Mar 14, 2025 at 5:48 am
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MathBot Answer:
3a+5a(2a+4ab−1a)=5a(4ab+a)+3a\displaystyle 3 a + 5 a \left(2 a + 4 a b - 1 a\right) = 5 a \left(4 a b + a\right) + 3 a 3a+5a(2a+4ab−1a)=5a(4ab+a)+3a
3a+5a(2a+4ab−1a)=20a2b+5a2+3a3 a + 5 a \left(2 a + 4 a b - 1 a\right) = 20 a^{2} b + 5 a^{2} + 3 a3a+5a(2a+4ab−1a)=20a2b+5a2+3a
3a+5a(2a+4ab−1a)=a(20ab+5a+3)3 a + 5 a \left(2 a + 4 a b - 1 a\right) = a \left(20 a b + 5 a + 3\right)3a+5a(2a+4ab−1a)=a(20ab+5a+3)