Log[Surd[3,89],89]=Log[3,1+156439158013135566809583929900068430197322593539878464330584390765793115800765532364991158267799986171544832057153043297510378966030569899821039254081856429682116922967005982/156680685593128735116469414263507931151942452455237187075345306836120946508566184857046513600898434447508872899346887025523794884632195838165633230326945156037679213625378427]+363

asked by guest
on Aug 01, 2025 at 1:07 pm



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