k^4+k^3-11*k^2-9*k+18
asked by guest on Apr 04, 2025 at 10:15 pm
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MathBot Answer:
k4+k3−11k2−9k+18=k4+k3−11k2−9k+18\displaystyle {k}^{4} + {k}^{3} - 11 {k}^{2} - 9 k + 18 = k^{4} + k^{3} - 11 k^{2} - 9 k + 18 k4+k3−11k2−9k+18=k4+k3−11k2−9k+18
k4+k3−11k2−9k+18=(k−3)(k−1)(k+2)(k+3){k}^{4} + {k}^{3} - 11 {k}^{2} - 9 k + 18 = \left(k - 3\right) \left(k - 1\right) \left(k + 2\right) \left(k + 3\right)k4+k3−11k2−9k+18=(k−3)(k−1)(k+2)(k+3)
