ln(x^2/(1-x))=lnx+ln(2x/(1+x))
You asked:
Solve the equation \(\ln\left( \frac{{x}^{2}}{1 - x} \right) = \ln\left( x \right) + \ln\left( \frac{2 x}{1 + x} \right)\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = \frac{1}{3} = 0.\overline{3}\]