ddx\frac{d}{dx}dxd sinx\sqrt{sin x}sinx
asked by guest on Jan 19, 2025 at 8:51 am
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MathBot Answer:
ddx[sin(x)]=cos(x)2sin(x)\frac{d}{dx}\left[\sqrt{\sin\left( x \right)}\right] = \frac{\cos{\left(x \right)}}{2 \sqrt{\sin{\left(x \right)}}}dxd[sin(x)]=2sin(x)cos(x)