\(\lim _{x\rightarrow 2}\left(bx^{2}+5x-4\right)=-2\)
You asked:
Investigate the equation: \(\lim_{x \to 2}{b \cdot {x}^{2} + 5 x - 4} = -2\).
MathBot Answer:
The solution is: \[b = -2\]
\[\begin{aligned}4 b + 6 &= -2\\4 b &= -8\\b &= -2\end{aligned}\]