Prove that ∬ 𝑑𝑆
𝑆
= 4𝜋
√𝑎𝑏𝑐
√𝑎2𝑥2+𝑏2𝑦2+𝑐2𝑧2
, where 𝑆 is the ellipsoid 𝑎𝑥2 + 𝑏𝑦2 + 𝑐𝑧2 = 1.
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Prove that ∬ 𝑑𝑆
𝑆
= 4𝜋
√𝑎𝑏𝑐
√𝑎2𝑥2+𝑏2𝑦2+𝑐2𝑧2
, where 𝑆 is the ellipsoid 𝑎𝑥2 + 𝑏𝑦2 + 𝑐𝑧2 = 1.
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.