(D^2+2)y=e^xcosx

asked by guest
on Apr 01, 2025 at 11:48 am



You asked:

Investigate the equation: (D2+2)⋅y=excos⁡(x)\left({D}^{2} + 2\right) \cdot y = {e}^{x} \cos\left( x \right).

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