3(2-5)+2(-3-1-1)

asked by guest
on Mar 23, 2025 at 1:22 pm



You asked:

Evaluate the expression: 3(2−5)+2(−3−1−1)3 \left(2 - 5\right) + 2 \left(-3 - 1 - 1\right)

MathBot Answer:

3(2−5)+2(−3−1−1)=−193 \left(2 - 5\right) + 2 \left(-3 - 1 - 1\right) = -19

3(2−5)+2(−3−1−1)=3⋅−3+2(−3−1−1)=−9+2(−3−1−1)=−9+2(−4−1)=−9+2⋅−5=−9+−10=−19\begin{aligned}3 \left(2 - 5\right) + 2 \left(-3 - 1 - 1\right)&=3 \cdot -3 + 2 \left(-3 - 1 - 1\right)\\&=-9 + 2 \left(-3 - 1 - 1\right)\\&=-9 + 2 \left(-4 - 1\right)\\&=-9 + 2 \cdot -5\\&=-9 + -10\\&=-19\end{aligned}

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