(15)−2/15(\frac{1}{5})^{-2} / \frac{1}{5}(51)−2/51
asked by guest on Apr 13, 2025 at 12:59 pm
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MathBot Answer:
(15)−215=125\frac{{\left( \frac{1}{5} \right)}^{-2}}{\frac{1}{5}} = 12551(51)−2=125
(15)−215=2515=125\begin{aligned}\frac{{\left( \frac{1}{5} \right)}^{-2}}{\frac{1}{5}}&=\frac{25}{\frac{1}{5}}\\&=125\end{aligned}51(51)−2=5125=125