((3mn^4/m^0n^-3))^2
asked by guest on Nov 17, 2024 at 7:48 pm
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MathBot Answer:
(3mn4m0n−3)2=9m2n14{\left( \frac{3 m {n}^{4}}{{m}^{0} {n}^{-3}} \right)}^{2} = 9 m^{2} n^{14}(m0n−33mn4)2=9m2n14