(x-3)(6x+1)=
asked by guest on Mar 29, 2025 at 4:52 pm
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MathBot Answer:
(x−3)(6x+1)=(6x+1)(x−3)\displaystyle \left(x - 3\right) \left(6 x + 1\right) = \left(6 x + 1\right) \left(x - 3\right) (x−3)(6x+1)=(6x+1)(x−3)
(x−3)(6x+1)=6x2−17x−3\left(x - 3\right) \left(6 x + 1\right) = 6 x^{2} - 17 x - 3(x−3)(6x+1)=6x2−17x−3