x raised to n = 27000 , find x

asked by guest
on Nov 16, 2024 at 10:44 pm



You asked:

Solve the equation xn=27000{x}^{n} = 27000 for the unknown xx.

MathBot Answer:

xn−27000=0∧−∞<x∧x<∞x^{n} - 27000 = 0 \wedge -\infty < x \wedge x < \infty

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