(7𝑥^2-3𝑦^3/4)^2
You asked:
Evaluate the expression: \({\left( 7 \cdot {x}^{2} - \frac{3 \cdot {y}^{3}}{4} \right)}^{2}\)
MathBot Answer:
Evaluated
\(\displaystyle {\left( 7 \cdot {x}^{2} - \frac{3 \cdot {y}^{3}}{4} \right)}^{2} = \left(7 x^{2} - \frac{3 y^{3}}{4}\right)^{2} \)
Expanded
\[{\left( 7 \cdot {x}^{2} - \frac{3 \cdot {y}^{3}}{4} \right)}^{2} = 49 x^{4} - \frac{21 x^{2} y^{3}}{2} + \frac{9 y^{6}}{16}\]
Factored
\[{\left( 7 \cdot {x}^{2} - \frac{3 \cdot {y}^{3}}{4} \right)}^{2} = \frac{\left(28 x^{2} - 3 y^{3}\right)^{2}}{16}\]