1 + 5 + 9 + ... + (4n – 3) = n(2n – 1) for all n 1.
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
1 + 5 + 9 + ... + (4n – 3) = n(2n – 1) for all n 1.
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.