\sum _{n=1}^{\infty \:}\left(\frac{\left(12n+sin^2\left(n^3+1\right)\right)}{5n^2+n}\right)

asked by guest
on Mar 29, 2025 at 4:38 pm



You asked:

Evaluate the expression: n=112n+sin(n3+1)25n2+n\sum_{n = 1}^{\infty} {\frac{12 n + {\sin\left( {n}^{3} + 1 \right)}^{2}}{5 {n}^{2} + n}}