x 2^{2}2+3x-40
asked by guest on Apr 01, 2025 at 12:34 pm
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MathBot Answer:
x2+3x−40=x2+3x−40\displaystyle {x}^{2} + 3 x - 40 = x^{2} + 3 x - 40 x2+3x−40=x2+3x−40
x2+3x−40=(x−5)(x+8){x}^{2} + 3 x - 40 = \left(x - 5\right) \left(x + 8\right)x2+3x−40=(x−5)(x+8)