asked by guest
on Apr 10, 2025 at 2:03 am
You asked:
Evaluate the expression:
20x2
MathBot Answer:
Evaluated
20x2=25x2
Roots
20x2=i4(20(re(x))2−20(im(x))2)2+1600(re(x))2(im(x))2sin2atan2(40re(x)im(x),20(re(x))2−20(im(x))2)+4(20(re(x))2−20(im(x))2)2+1600(re(x))2(im(x))2cos2atan2(40re(x)im(x),20(re(x))2−20(im(x))2)≈6.32455532033676i(0.25((re(x))2−(im(x))2)2+(re(x))2(im(x))2)0.25sin2atan2(40re(x)im(x),20(re(x))2−20(im(x))2)+6.32455532033676(0.25((re(x))2−(im(x))2)2+(re(x))2(im(x))2)0.25cos2atan2(40re(x)im(x),20(re(x))2−20(im(x))2)20x2=i−4(20(re(x))2−20(im(x))2)2+1600(re(x))2(im(x))2sin2atan2(40re(x)im(x),20(re(x))2−20(im(x))2)−4(20(re(x))2−20(im(x))2)2+1600(re(x))2(im(x))2cos2atan2(40re(x)im(x),20(re(x))2−20(im(x))2)≈−6.32455532033676i(0.25((re(x))2−(im(x))2)2+(re(x))2(im(x))2)0.25sin2atan2(40re(x)im(x),20(re(x))2−20(im(x))2)−6.32455532033676(0.25((re(x))2−(im(x))2)2+(re(x))2(im(x))2)0.25cos2atan2(40re(x)im(x),20(re(x))2−20(im(x))2)