(1) Consider the following equations.
(a) Solve the equation
2025
=
𝑒
3
𝑒
2
𝑥
+
4
−
4
2025=e
3e
2x+4
−4
exactly.
(b) Solve the equation
ln
(
ln
(
ln
(
𝑥
+
7
)
+
3
)
)
=
2025
ln(ln(ln(x+7)+3))=2025 exactly.
5 + 5 = 10 marks
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