∫−∞∞12πNpqe−(k−Np)22Npq \int_{-\infty}^{\infty}\frac{1}{\sqrt{2\pi Npq}}e^{-\frac{\left(k-Np\right)^2}{2Npq}}

asked by guest
on Mar 29, 2025 at 11:03 pm




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