(14/7) + {(16/4)-[(3/6)*((2/8)+(2/4))/(4/5)]}*(4/5)
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MathBot Answer:
\[\frac{14}{7} + \left(\frac{16}{4} - \frac{\frac{3}{6} \left(\frac{2}{8} + \frac{2}{4}\right)}{\frac{4}{5}}\right) \cdot \frac{4}{5} = \frac{193}{40} = 4.825\]
\[\begin{aligned}\frac{14}{7} + \left(\frac{16}{4} - \frac{\frac{3}{6} \left(\frac{2}{8} + \frac{2}{4}\right)}{\frac{4}{5}}\right) \cdot \frac{4}{5}& = \frac{14}{7} + \left(\frac{16}{4} - \frac{3}{6} \cdot \left(\frac{2}{8} + \frac{2}{4}\right) \cdot \frac{1}{\frac{4}{5}}\right) \cdot \frac{4}{5}\\& = \frac{14}{7} + \left(\frac{16}{4} - \frac{3}{6} \cdot \frac{3}{4} \cdot \frac{1}{\frac{4}{5}}\right) \cdot \frac{4}{5}\\& = \frac{14}{7} + \left(\frac{16}{4} - \frac{3}{6} \cdot \frac{15}{16}\right) \cdot \frac{4}{5}\\& = \frac{14}{7} + \left(\frac{16}{4} - \frac{15}{32}\right) \cdot \frac{4}{5}\\& = \frac{14}{7} + \frac{113}{32} \cdot \frac{4}{5}\\& = \frac{14}{7} + \frac{113}{40}\\& = \frac{193}{40}\end{aligned}\]