find the inverse of matrix by gauss jordan method
$$\begin{bmatrix} 1 & 2 & 1 \\\\ 2 & 1 & 1 \\\\ 8 & 4 & 3 \end{bmatrix}$$
MathBot Answer:
The inverse is: \[ \left[\begin{matrix}- \frac{1}{3} & - \frac{2}{3} & \frac{1}{3}\\\frac{2}{3} & - \frac{5}{3} & \frac{1}{3}\\0 & 4 & -1\end{matrix}\right] \] The inverse of a square matrix \(A\), is the matrix \(A^{-1}\) such that: \[ A^{-1} A = A A^{-1} = I \] where \(I\) is the identity matrix.