How to find b when 1/b-5 - 10/b^2-5b+25 = 1/b+5
You asked:
Solve the equation \(\frac{1}{b} - 5 - \frac{10}{{b}^{2}} - 5 b + 25 = \frac{1}{b} + 5\) for the variable \(b\).
MathBot Answer:
The 3 solutions to the equation are: \[\begin{aligned}b &= 1\\b &= 1 + \sqrt{3} \approx 2.7320508\\b &= 1 - \sqrt{3} \approx -0.73205081\end{aligned}\]