((𝑥 + 1)*(𝑥^2 + 𝑦^2 + 1))*𝑑𝑥 + (𝑦*(𝑥 + 1)^2)*𝑑𝑦 = 0

asked by guest
on Oct 26, 2024 at 9:27 am



You asked:

Investigate the equation: \(\left(x + 1\right) \cdot \left({x}^{2} + {y}^{2} + 1\right) \cdot d x + y \cdot {\left( x + 1 \right)}^{2} \cdot d y = 0\).

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