log10(PEthanol )=8.1122-(1592.864/(89.15+226.184))
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
log10(PEthanol )=8.1122-(1592.864/(89.15+226.184))
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.