A=1000(1+0.01/4)^16

Ic=1040-1000

asked by guest
on Nov 14, 2024 at 10:34 pm



You asked:

Solve the system of equations:A=1000(1+0.014)16Ic=1040−1000\begin{aligned}A &= 1000 {\left( 1 + \frac{0.01}{4} \right)}^{16}\\I c &= 1040 - 1000\end{aligned}

MathBot Answer:

The system of equations has infinitely many solutions.

A=447002510146167025761419341542947859206401429496729600000000000000000000000000000I=40c\begin{aligned}A &= \frac{447002510146167025761419341542947859206401}{429496729600000000000000000000000000000}\\I &= \frac{40}{c}\end{aligned}

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