1/x+1 + 1/y+1 + 1/z+1
asked by guest on Feb 01, 2025 at 5:50 am
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MathBot Answer:
1x+1+1y+1+1z+1=3+1z+1y+1x\displaystyle \frac{1}{x} + 1 + \frac{1}{y} + 1 + \frac{1}{z} + 1 = 3 + \frac{1}{z} + \frac{1}{y} + \frac{1}{x} x1+1+y1+1+z1+1=3+z1+y1+x1
1x+1+1y+1+1z+1=3xyz+xy+xz+yzxyz\frac{1}{x} + 1 + \frac{1}{y} + 1 + \frac{1}{z} + 1 = \frac{3 x y z + x y + x z + y z}{x y z}x1+1+y1+1+z1+1=xyz3xyz+xy+xz+yz