(7x+1)(4x-2)-(5x+2)(8x+1)

asked by guest
on Nov 25, 2024 at 1:31 pm



You asked:

Evaluate the expression: \(\left(7 x + 1\right) \cdot \left(4 x - 2\right) - \left(5 x + 2\right) \cdot \left(8 x + 1\right)\)

MathBot Answer:

Evaluated



\(\displaystyle \left(7 x + 1\right) \cdot \left(4 x - 2\right) - \left(5 x + 2\right) \cdot \left(8 x + 1\right) = \left(4 x - 2\right) \left(7 x + 1\right) - \left(5 x + 2\right) \left(8 x + 1\right) \)

Expanded

\[\left(7 x + 1\right) \cdot \left(4 x - 2\right) - \left(5 x + 2\right) \cdot \left(8 x + 1\right) = - 12 x^{2} - 31 x - 4\]

Factored

\[\left(7 x + 1\right) \cdot \left(4 x - 2\right) - \left(5 x + 2\right) \cdot \left(8 x + 1\right) = - 12 x^{2} - 31 x - 4\]

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