inverse matrix to ([sp.cos(t),-sp.sin(t),-u*sp.cos(t) + u + v*sp.sin(t)],[sp.sin(t),sp.cos(t),-u*sp.sin(t) - v*sp.cos(t) + v],[0,0,1])

asked by guest
on Oct 18, 2024 at 3:17 am



Mathbot Says...

I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.