∫_0^1▒1/(x^2+3x-2)=
You asked:
Evaluate the integral: \(\int_{0}^{1}{\frac{1}{{x}^{2} + 3 x - 2}}dx\)
MathBot Answer:
Definite integral
\[\int_{0}^{1}{\frac{1}{{x}^{2} + 3 x - 2}}dx = \text{NaN}\]
∫_0^1▒1/(x^2+3x-2)=
You asked:
MathBot Answer:
\[\int_{0}^{1}{\frac{1}{{x}^{2} + 3 x - 2}}dx = \text{NaN}\]