(-7-1-8)➗(-14+4+4-2)-[-(-3+2)×(-3-2)]-(-1)

asked by guest
on Nov 17, 2024 at 2:36 am



You asked:

Evaluate the expression: \(\frac{-7 - 1 - 8}{-14 + 4 + 4 - 2} - -\left( -3 + 2 \right) \cdot \left(-3 - 2\right) - -1\)

MathBot Answer:

\[\frac{-7 - 1 - 8}{-14 + 4 + 4 - 2} - -\left( -3 + 2 \right) \cdot \left(-3 - 2\right) - -1 = 8\]

\[\begin{aligned}\frac{-7 - 1 - 8}{-14 + 4 + 4 - 2} - -\left( -3 + 2 \right) \cdot \left(-3 - 2\right) - -1& = \left(-7 - 1 - 8\right) \cdot \frac{1}{-14 + 4 + 4 - 2} - - \cdot \left(-3 + 2\right) \cdot \left(-3 - 2\right) + 1\\& = \left(-8 - 8\right) \cdot \frac{1}{-14 + 4 + 4 - 2} - - \cdot \left(-3 + 2\right) \cdot \left(-3 - 2\right) + 1\\& = -16 \cdot \frac{1}{-14 + 4 + 4 - 2} - - \cdot \left(-3 + 2\right) \cdot \left(-3 - 2\right) + 1\\& = -16 \cdot \frac{1}{-10 + 4 - 2} - - \cdot \left(-3 + 2\right) \cdot \left(-3 - 2\right) + 1\\& = -16 \cdot \frac{1}{-6 - 2} - - \cdot \left(-3 + 2\right) \cdot \left(-3 - 2\right) + 1\\& = \frac{-16}{-8} - - \cdot \left(-3 + 2\right) \cdot \left(-3 - 2\right) + 1\\& = 2 - - \cdot \left(-3 + 2\right) \cdot \left(-3 - 2\right) + 1\\& = 2 - - \cdot -1 \cdot \left(-3 - 2\right) + 1\\& = 2 - - \cdot -1 \cdot -5 + 1\\& = 2 - 1 \cdot -5 + 1\\& = 2 - -5 + 1\\& = 2 + 5 + 1\\& = 7 + 1\\& = 8\end{aligned}\]

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