QD = 1.36 – 0.373 PD

QD x PD = 0.185

asked by guest
on Apr 05, 2025 at 12:15 am



You asked:

Solve the system of equations:QD=1.360.373PDQDxPD=0.185\begin{aligned}Q D &= 1.36 - 0.373 P D\\Q D x P D &= 0.185\end{aligned}

MathBot Answer:

The system of equations has infinitely many solutions.

D=13602720005Qx(92480x13801)13801+1000Q(184960x13801)13801+1000QP={2720005Qx(92480x13801)5147773+1000Q(184960x13801)5147773}{1000Q373}Q={Q}{373P1000}\begin{aligned}D &= \frac{1360}{- \frac{272000 \sqrt{5} Q \sqrt{x \left(92480 x - 13801\right)}}{13801} + \frac{1000 Q \left(184960 x - 13801\right)}{13801} + 1000 Q}\\P &= \left\{- \frac{272000 \sqrt{5} Q \sqrt{x \left(92480 x - 13801\right)}}{5147773} + \frac{1000 Q \left(184960 x - 13801\right)}{5147773}\right\} \setminus \left\{- \frac{1000 Q}{373}\right\}\\Q &= \left\{Q\right\} \setminus \left\{- \frac{373 P}{1000}\right\}\end{aligned}

xx is a free variable.