y'' + y' -2y = 0
You asked:
Solve the equation \(y^{\prime \prime} + y^{\prime} - 2 y = 0\) for the variable \(y\).
MathBot Answer:
\[y{\left(t \right)} = C_{1} e^{- 2 t} + C_{2} e^{t}\]
\(C_{1}\), \(C_{2}\) are arbitrary constants.
\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).