x*1,2+(1-X)*(0)

asked by guest
on Oct 24, 2024 at 2:20 am



MathBot Answer:

The sum of \(x \cdot 1\) and \(2 + \left(1 - X\right) \cdot 0\) is:

\[\begin{aligned}&=\left(x \cdot 1\right) + \left(2 + \left(1 - X\right) \cdot 0\right) \\\\ &= x 1 + \left(1 - X\right) 0 + 2 \\\\ &= x + 2 \\\\\end{aligned}\]

The difference of \(x \cdot 1\) and \(2 + \left(1 - X\right) \cdot 0\) is:

\[\begin{aligned}&=\left(x \cdot 1\right) - \left(2 + \left(1 - X\right) \cdot 0\right) \\\\ &= x 1 - \left(1 - X\right) 0 - 2 \\\\ &= x - 2 \\\\\end{aligned}\]

The product of \(x \cdot 1\) and \(2 + \left(1 - X\right) \cdot 0\) is:

\[\begin{aligned}&=\left(x \cdot 1\right) \cdot \left(2 + \left(1 - X\right) \cdot 0\right) \\\\ &= x \left(\left(1 - X\right) 0 + 2\right) \\\\ &= 2 x \\\\\end{aligned}\]

The quotient of \(x \cdot 1\) and \(2 + \left(1 - X\right) \cdot 0\) is:

\[\begin{aligned}&= \frac{\left(x \cdot 1\right)}{\left(2 + \left(1 - X\right) \cdot 0\right)} \\\\ &= \frac{x}{\left(1 - X\right) 0 + 2} \\\\ &= \frac{x}{2} \\\\\end{aligned}\]

+ Submit Question