32^0,4
MathBot Answer:
The sum of \({32}^{0}\) and \(4\) is:
\[\begin{aligned}&=\left({32}^{0}\right) + \left(4\right) \\\\ &= 5 \\\\\end{aligned}\]
The difference of \({32}^{0}\) and \(4\) is:
\[\begin{aligned}&=\left({32}^{0}\right) - \left(4\right) \\\\ &= -3 \\\\\end{aligned}\]
The product of \({32}^{0}\) and \(4\) is:
\[\begin{aligned}&=\left({32}^{0}\right) \cdot \left(4\right) \\\\ &= 4 \\\\\end{aligned}\]
The quotient of \({32}^{0}\) and \(4\) is:
\[\begin{aligned}&= \frac{\left({32}^{0}\right)}{\left(4\right)} \\\\ &= \frac{1}{4} \\\\\end{aligned}\]