x + y + z = 6 x + 2z = 7 3x + y + z = 12 solve using inverse
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
x + y + z = 6 x + 2z = 7 3x + y + z = 12 solve using inverse
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.