sin 2x /sin 3x + cos 2x/ cos 3x = 2sin 5x cosec 6x

asked by guest
on Nov 25, 2024 at 9:42 am



You asked:

Solve the equation \(\frac{\sin\left( 2 x \right)}{\sin\left( 3 x \right)} + \frac{\cos\left( 2 x \right)}{\cos\left( 3 x \right)} = 2 \cdot \sin\left( 5 x \right) \cdot \csc\left( 6 x \right)\) for the variable \(x\).

MathBot Answer:

The complex solutions are: \[\mathbb{C}\]

+ Submit Question