derivative of 𝑦 = csch 𝜃 (1 − ln csch 𝜃)
asked by guest on Dec 30, 2024 at 3:18 pm
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MathBot Answer:
dydθ=−(1−log(csch(θ)))coth(θ)csch(θ)+coth(θ)csch(θ)\frac{d y}{d θ} = - \left(1 - \log{\left(\operatorname{csch}{\left(θ \right)} \right)}\right) \coth{\left(θ \right)} \operatorname{csch}{\left(θ \right)} + \coth{\left(θ \right)} \operatorname{csch}{\left(θ \right)}dθdy=−(1−log(csch(θ)))coth(θ)csch(θ)+coth(θ)csch(θ)