derivative of 𝑦 = csch 𝜃 (1 − ln csch 𝜃)

asked by guest
on Dec 30, 2024 at 3:18 pm



You asked:

Find the derivative of the function y=csch⁡(θ)(1−ln⁡(csch⁡(θ)))y = \operatorname{csch}\left( θ \right) \left(1 - \ln\left( \operatorname{csch}\left( θ \right) \right)\right) with respect to θθ.

MathBot Answer:

dydθ=−(1−log⁡(csch⁡(θ)))coth⁡(θ)csch⁡(θ)+coth⁡(θ)csch⁡(θ)\frac{d y}{d θ} = - \left(1 - \log{\left(\operatorname{csch}{\left(θ \right)} \right)}\right) \coth{\left(θ \right)} \operatorname{csch}{\left(θ \right)} + \coth{\left(θ \right)} \operatorname{csch}{\left(θ \right)}

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