solve 9b + 9c + 7d + 10e + 26f + 13g = 600, 15a + 9c + 2e + 13g = 900, 15e + 8f = 400, 21a + 13b + 9c + 7d + 13g = 1200

asked by guest
on Jan 13, 2025 at 9:09 am



You asked:

Solve the system of equations:9b+9c+7d+10e+26f+13g=60015a+9c+2e+13g=90015e+8f=40021a+13b+9c+7d+13g=1200\begin{aligned}9 b + 9 c + 7 d + 10 e + 26 f + 13 g &= 600\\15 a + 9 c + 2 e + 13 g &= 900\\15 e + 8 f &= 400\\21 a + 13 b + 9 c + 7 d + 13 g &= 1200\end{aligned}

MathBot Answer:

The system of equations has infinitely many solutions.

a=28d249−2047e996+23500249b=−49d83−170083+183e166c=−140d747−13g9−42800747+9571e2988f=50−15e8\begin{aligned}a &= \frac{28 d}{249} - \frac{2047 e}{996} + \frac{23500}{249}\\b &= - \frac{49 d}{83} - \frac{1700}{83} + \frac{183 e}{166}\\c &= - \frac{140 d}{747} - \frac{13 g}{9} - \frac{42800}{747} + \frac{9571 e}{2988}\\f &= 50 - \frac{15 e}{8}\end{aligned}

dd is a free variable.


gg is a free variable.

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