3x−4x+4\frac{3x-4}{x+4}x+43x−4
asked by guest on Mar 19, 2025 at 6:10 pm
You asked:
MathBot Answer:
3x−4x+4=3x−4x+4\displaystyle \frac{3 x - 4}{x + 4} = \frac{3 x - 4}{x + 4} x+43x−4=x+43x−4
3x−4x+4=3xx+4−4x+4\frac{3 x - 4}{x + 4} = \frac{3 x}{x + 4} - \frac{4}{x + 4}x+43x−4=x+43x−x+44