(2x ^ { 2 } +x+4-3x ^ { 3 } ) \div (x-5)

asked by guest
on Mar 26, 2025 at 8:44 pm



You asked:

Evaluate the expression: 2x2+x+4−3x3x−5\frac{2 {x}^{2} + x + 4 - 3 {x}^{3}}{x - 5}

MathBot Answer:

Evaluated



2x2+x+4−3x3x−5=−3x3+2x2+x+4x−5\displaystyle \frac{2 {x}^{2} + x + 4 - 3 {x}^{3}}{x - 5} = \frac{- 3 x^{3} + 2 x^{2} + x + 4}{x - 5}

Expanded

2x2+x+4−3x3x−5=−3x3x−5+2x2x−5+xx−5+4x−5\frac{2 {x}^{2} + x + 4 - 3 {x}^{3}}{x - 5} = - \frac{3 x^{3}}{x - 5} + \frac{2 x^{2}}{x - 5} + \frac{x}{x - 5} + \frac{4}{x - 5}

Factored

2x2+x+4−3x3x−5=−3x3−2x2−x−4x−5\frac{2 {x}^{2} + x + 4 - 3 {x}^{3}}{x - 5} = - \frac{3 x^{3} - 2 x^{2} - x - 4}{x - 5}

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