x+y = 2
3x+2y = 0
Solve for x and y
You asked:
Given \( x + y = 2 \), \( 3 x + 2 y = 0 \), evaluate \( x \), \( y \).
MathBot Answer:
The system of linear equations has exactly one solution.
\[x = -4\]
\[y = 6\]
Solve \(x + y = 2\) for \(x\). \[x = 2 - y\]
Substitute \(2 - y\) for \(x\) in \(3 x + 2 y = 0\) and simplify. $$\begin{aligned}3 x + 2 y &= 0 \\ 3 \left(2 - y\right) + 2 y &= 0 \\ y &= 6 \end{aligned}$$
Use substitution of the numerical value of \(y\) to get the values of \(x\). $$\begin{aligned}x &= 2 - y \\ x &= 2 - 6 \\ x &= -4\end{aligned}$$