4*n^2 + 73*n + 333

factorize

asked by guest
on Nov 23, 2024 at 3:13 pm



You asked:

Factor the expression: \(\displaystyle 4 {n}^{2} + 73 n + 333\)

MathBot Answer:

Factorization over the rational numbers:

\[\left(4 n + 37\right) \left(n + 9\right)\]

+ Submit Question