(ln(e^y))^2=
You asked:
Evaluate the expression: \({\ln\left( {e}^{y} \right)}^{2}\)
MathBot Answer:
\[{\ln\left( {e}^{y} \right)}^{2} = \log{\left(e^{y} \right)}^{2}\]
\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).