asked by guest
on Jan 20, 2025 at 7:45 am
MathBot Answer:
Slope-Intercept Form:
$$\begin{aligned} y = mx+b\end{aligned}$$$$\begin{aligned}y &= 4x + b \\ 2 &= 4 \times -1 + b \\ 2 &= -4 + b \\ b &= 6 \end{aligned}$$An equation of the line in slope-intercept form is: $y = 4 x + 6$
Point-Slope Form:
$$\begin{aligned} y - y_{1} = m(x - x_{1}) \end{aligned}$$$$ \text{where m } = 4, \text{ } x_{1} = -1, \text{ and } y_{1} = 2 $$An equation of the line in point-slope form is: $y - 2 = 4 \left(x + 1\right)$
Standard Form:
$$\begin{aligned}Ax + By + C = 0\end{aligned}$$$$\begin{aligned} \text{Slope} &= -\frac{A}{B} \\ -\frac{A}{B} &= \frac{4}{1} \\ A = -4, B = 1 \end{aligned}$$$$\begin{aligned}-4 x + 1 y + C &= 0 \\ -4(-1) + 1(2) + C &= 0 \\ 4 + 2 + C &= 0 \\ 4 + C &= -2 \\ C &= -6 \end{aligned}$$An equation of the line in standard form is: $4 x - y + 6 = 0$