divide (3x^3-5x^2-16x+12) by (x+2)

asked by guest
on Sep 22, 2024 at 2:14 am



You asked:

Evaluate the expression: \(\frac{3 \cdot {x}^{3} - 5 \cdot {x}^{2} - 16 x + 12}{x + 2}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{3 \cdot {x}^{3} - 5 \cdot {x}^{2} - 16 x + 12}{x + 2} = \frac{3 x^{3} - 5 x^{2} - 16 x + 12}{x + 2} \)

Expanded

\[\frac{3 \cdot {x}^{3} - 5 \cdot {x}^{2} - 16 x + 12}{x + 2} = \frac{3 x^{3}}{x + 2} - \frac{5 x^{2}}{x + 2} - \frac{16 x}{x + 2} + \frac{12}{x + 2}\]

Factored

\[\frac{3 \cdot {x}^{3} - 5 \cdot {x}^{2} - 16 x + 12}{x + 2} = \left(3 x - 2\right) \left(x - 3\right)\]

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