2^2x + 2^x+2 - 32 = 0

asked by guest
on Sep 22, 2024 at 5:25 pm



You asked:

Solve the equation \({2}^{2} \cdot x + {2}^{x} + 2 - 32 = 0\) for the variable \(x\).

MathBot Answer:

The solution is: \[x = \frac{-2.52110090092585954056389187027322294975967887896 + \frac{15 \log{\left(2 \right)}}{2}}{\log{\left(2 \right)}} \approx 3.8628202\]

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