\frac{21x^2+22x-8}{3x+4}

asked by guest
on Sep 21, 2024 at 7:10 am



You asked:

Evaluate the expression: \(\frac{21 \cdot {x}^{2} + 22 x - 8}{3 x + 4}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{21 \cdot {x}^{2} + 22 x - 8}{3 x + 4} = \frac{21 x^{2} + 22 x - 8}{3 x + 4} \)


Expanded

\[\frac{21 \cdot {x}^{2} + 22 x - 8}{3 x + 4} = \frac{21 x^{2}}{3 x + 4} + \frac{22 x}{3 x + 4} - \frac{8}{3 x + 4}\]


Factored

\[\frac{21 \cdot {x}^{2} + 22 x - 8}{3 x + 4} = 7 x - 2\]