dy/dx * x^2 = 2y/x - y^2/x^2

asked by guest
on Mar 23, 2025 at 6:02 am



You asked:

Investigate the equation: dydxx2=2yx−y2x2\frac{d y}{d x} {x}^{2} = \frac{2 y}{x} - \frac{{y}^{2}}{{x}^{2}}.

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