H(a)wk=2^a solve for a
You asked:
Solve the equation \[H\left( a \right) \cdot w k = {2}^{a}\] for the unknown \(a\).
MathBot Answer:
\(- 2^{a} + k w H{\left(a \right)} = 0 \wedge -\infty < a \wedge a < \infty\)
H(a)wk=2^a solve for a
You asked:
MathBot Answer:
\(- 2^{a} + k w H{\left(a \right)} = 0 \wedge -\infty < a \wedge a < \infty\)